How to convert nautical leagues to atomic units of length
1 nautical league (int.) is equal to 104,993,183,500,000 atomic units of length, and 1 a.u. of length is equal to 9.524427842 × 10⁻¹⁵ nautical leagues. To convert, multiply by the conversion factor:
atomic units of length = nautical leagues × 104,993,183,500,000
atomic units of length = nautical leagues ÷ 9.524427842 × 10⁻¹⁵Example: convert 1 NL to a₀: 1 × 104,993,183,500,000 = 104,993,183,500,000 a₀.
Nautical League (int.) to A.u. of Length conversion table
| Nautical League (int.) (NL) | A.u. of Length (a₀) |
|---|---|
| 0.01 NL | 1,049,931,835,000 a₀ |
| 0.1 NL | 10,499,318,350,000 a₀ |
| 1 NL | 104,993,183,500,000 a₀ |
| 2 NL | 209,986,367,000,000 a₀ |
| 3 NL | 314,979,550,500,000 a₀ |
| 5 NL | 524,965,917,400,000 a₀ |
| 10 NL | 1.049931835 × 10¹⁵ a₀ |
| 20 NL | 2.09986367 × 10¹⁵ a₀ |
| 50 NL | 5.249659174 × 10¹⁵ a₀ |
| 100 NL | 1.049931835 × 10¹⁶ a₀ |
| 250 NL | 2.624829587 × 10¹⁶ a₀ |
| 500 NL | 5.249659174 × 10¹⁶ a₀ |
| 1,000 NL | 1.049931835 × 10¹⁷ a₀ |
About the nautical league (int.)
The international nautical league is 3 nautical miles (5,556 m).
Symbol: NL · 1 NL = 5,556 m · Category: Nautical
About the a.u. of length
The atomic unit of length is the Bohr radius, about 5.29 × 10⁻¹¹ m: the most probable distance between the proton and electron in a hydrogen atom.
Symbol: a₀ · 1 a₀ = 5.291772109 × 10⁻¹¹ m · Category: Atomic & physics