Skip to content
XUtilHub

Chain (US Survey) to Link (US Survey) Converter

Convert chains (US survey) (ch (US)) to links (US survey) (li (US)). 1 ch (US) = 100 li (US).

1 ch (US) = 100 li (US)

Link (US Survey) to Chain (US Survey) converter

How to convert chains (US survey) to links (US survey)

1 chain (us survey) is equal to 100 links (US survey), and 1 link (us survey) is equal to 0.01 chains (US survey). To convert, multiply by the conversion factor:

links (US survey) = chains (US survey) × 100
links (US survey) = chains (US survey) ÷ 0.01

Example: convert 15 ch (US) to li (US): 15 × 100 = 1,500 li (US).

Chain (US Survey) to Link (US Survey) conversion table

Chain (US Survey) (ch (US))Link (US Survey) (li (US))
0.01 ch (US)1 li (US)
0.1 ch (US)10 li (US)
1 ch (US)100 li (US)
2 ch (US)200 li (US)
3 ch (US)300 li (US)
5 ch (US)500 li (US)
10 ch (US)1,000 li (US)
20 ch (US)2,000 li (US)
50 ch (US)5,000 li (US)
100 ch (US)10,000 li (US)
250 ch (US)25,000 li (US)
500 ch (US)50,000 li (US)
1,000 ch (US)100,000 li (US)

About the chain (us survey)

The US survey chain is 66 US survey feet, about 20.11684 m, used in the US Public Land Survey System.

Symbol: ch (US) · 1 ch (US) = 20.11684023 m · Category: US survey units

About the link (us survey)

The US survey link is one hundredth of a US survey chain, about 0.2011684 m.

Symbol: li (US) · 1 li (US) = 0.2011684023 m · Category: US survey units

Frequently asked questions

How many links (US survey) are in a chain (us survey)?

There are 100 links (US survey) in 1 chain (us survey) (ch (US)).

How many chains (US survey) are in a link (us survey)?

1 link (us survey) (li (US)) equals 0.01 chains (US survey).

How do I convert chains (US survey) to links (US survey)?

Multiply the length in chains (US survey) by 100. For example, 15 ch (US) × 100 = 1,500 li (US).

How do I convert links (US survey) to chains (US survey)?

Divide the length in links (US survey) by 100, or multiply it by 0.01. You can also use the Link (US Survey) to Chain (US Survey) converter.